document.write( "Question 906075: Makana invested $700 in a simple interest account that had an interest rate that was 3% more than that of her friend Marlys. If Marlys earned $39 after one year from an investment of $650, how much did Makana earn in one year? \n" ); document.write( "
Algebra.Com's Answer #550047 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 700*(x+3)/100=y \n" ); document.write( "7x+21=y\r \n" ); document.write( "\n" ); document.write( "650*x/100=39 \n" ); document.write( "6.5x=39 \n" ); document.write( "x=39/6.5=6 marlys rate of interest\r \n" ); document.write( "\n" ); document.write( "7x+21=y \n" ); document.write( "42+21=y \n" ); document.write( "y=63 Makana earned \n" ); document.write( " \n" ); document.write( " |