document.write( "Question 906075: Makana invested $700 in a simple interest account that had an interest rate that was 3% more than that of her friend Marlys. If Marlys earned $39 after one year from an investment of $650, how much did Makana earn in one year? \n" ); document.write( "
Algebra.Com's Answer #550047 by richwmiller(17219)\"\" \"About 
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700*(x+3)/100=y
\n" ); document.write( "7x+21=y\r
\n" ); document.write( "\n" ); document.write( "650*x/100=39
\n" ); document.write( "6.5x=39
\n" ); document.write( "x=39/6.5=6 marlys rate of interest\r
\n" ); document.write( "\n" ); document.write( "7x+21=y
\n" ); document.write( "42+21=y
\n" ); document.write( "y=63 Makana earned
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