document.write( "Question 906720: You wish to invest $800 over one year in two accounts paying 5% and 6% annually. How much should you invest in each to earn $43? \n" ); document.write( "
Algebra.Com's Answer #550029 by richwmiller(17219)\"\" \"About 
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Total amount of money invested: $800
\n" ); document.write( "x+y=800,
\n" ); document.write( "Total yearly interest for the two accounts is: $43
\n" ); document.write( "0.05*x+0.06*y=43
\n" ); document.write( "x=800-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.05*(800-y)+0.06*y=43
\n" ); document.write( "Multiply out
\n" ); document.write( "40-0.05y+0.06*y=43
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.01*y=3
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 300.00 at 6%
\n" ); document.write( "x=800-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 500.00 at 5%
\n" ); document.write( "Check
\n" ); document.write( "0.05*500+0.06*300=43
\n" ); document.write( "25+18=43
\n" ); document.write( "43=43
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
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