document.write( "Question 906706: I've struggling all day! Help much needed! Thanks :) \r
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document.write( "Two hikers,Alan and Ben,are 12.4 miles apart walking towards each other. They meet in 4 hours. What is the rate of each hiker if Ben walks 0.5 mph faster than Alan? \n" );
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Algebra.Com's Answer #550027 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Two hikers,Alan and Ben,are 12.4 miles apart walking towards each other. \n" ); document.write( " They meet in 4 hours. \n" ); document.write( " What is the rate of each hiker if Ben walks 0.5 mph faster than Alan? \n" ); document.write( ": \n" ); document.write( "Let s = Alan's walking rate \n" ); document.write( "then \n" ); document.write( "(s+.5) = Ben's walking rate \n" ); document.write( ": \n" ); document.write( "When they meet they will have walked a total 12.4 mi. \n" ); document.write( "Write a distance equation; dist = time * speed \n" ); document.write( ": \n" ); document.write( "Alan's dist + Ben's dist = 12.4 mi \n" ); document.write( "4s + 4(s+.5) = 12.4 \n" ); document.write( "4s + 4s + 2 = 12.4 \n" ); document.write( "8s = 12.4 - 2 \n" ); document.write( "8s = 10.4 \n" ); document.write( "s = 10.4/8 \n" ); document.write( "s = 1.3 mph is Alan's walking rate \n" ); document.write( "then \n" ); document.write( "1.3 + .5 = 1.8 mph is Ben's \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this find the actual dist each walked \n" ); document.write( "4 * 1.3 = 5.2 \n" ); document.write( "4 * 1.8 = 7.2 \n" ); document.write( "--------------- \n" ); document.write( "total dist: 12.4 mis \n" ); document.write( " |