document.write( "Question 906715: Solve each system of equation
\n" ); document.write( "3x+2y=12
\n" ); document.write( "x+y=3
\n" ); document.write( "This problem is really confusing me I tried changing them in y=mx+b but the answer still isn't right and then I tried multiplying the bottom equation by -3 and I get another wrong answer. Please help.
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Algebra.Com's Answer #550025 by richwmiller(17219)\"\" \"About 
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addition/elimination
\n" ); document.write( "3x+2y=12
\n" ); document.write( "x+y=3
\n" ); document.write( "3x+2y=12
\n" ); document.write( "-3x-3y=-9
\n" ); document.write( "add
\n" ); document.write( "-y=3
\n" ); document.write( "y=-3
\n" ); document.write( "x+y=3
\n" ); document.write( "x-3=3
\n" ); document.write( "x=6\r
\n" ); document.write( "\n" ); document.write( "substitution
\n" ); document.write( "3x+2y=12
\n" ); document.write( "x+y=3
\n" ); document.write( "y=3-x
\n" ); document.write( "3x+2(3-x)=12
\n" ); document.write( "3x+6-2x=12
\n" ); document.write( "x=6
\n" ); document.write( "x+y=3
\n" ); document.write( "6+y=3
\n" ); document.write( "y=-3\r
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