document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906662>Question 906662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've been stuck on this question and I'm pretty sure it's the most simplest things ever but I don't know why I can't figure it out. So far I got to a+b=1200 but I know I need another part of the system. the question is:\r<BR>\n" );
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document.write( " An office is printing 1200 copies of a document using two printers. Printer a gets jammed and prints only half as many copies as printer B. Write and solve a system of equations to for number of copies that eah printer will produce.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549989 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b=1200<BR>\n" );
document.write( "a gets jammed and prints only half as many copies as printer B.<BR>\n" );
document.write( "a=b/2 </SPAN>\n" );
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