document.write( "Question 906638: Two alcohol solutions are available: one containing 12% alcohol, and the other containing 37% alcohol. How many liters of the 37% alcohol solution -the second solution- must be used in order to obtain 32 liters of a mixture that contains 28% alcohol?\r
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Algebra.Com's Answer #549971 by richwmiller(17219)\"\" \"About 
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a+b=32,
\n" ); document.write( "0.37*a+0.12*b=0.28*32
\n" ); document.write( "a=32-b
\n" ); document.write( "0.37*(32-b)+0.12*b=8.96
\n" ); document.write( "11.84-0.37b+0.12*b=8.96
\n" ); document.write( "-0.25*b=-2.88
\n" ); document.write( "b=11.52
\n" ); document.write( "a=32-b
\n" ); document.write( "a=20.48 liter at 37%
\n" ); document.write( "b=11.52 liter at 12%\r
\n" ); document.write( "\n" ); document.write( "rounded
\n" ); document.write( "a=20.5 liter at 37%
\n" ); document.write( "b=11.5 liter at 12%
\n" ); document.write( "check
\n" ); document.write( "0.37*20.48+0.12*11.52=0.28*32
\n" ); document.write( "7.5776+1.3824=8.96
\n" ); document.write( "8.96=8.96
\n" ); document.write( "ok
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