document.write( "Question 76680: A consultant traveled 5 hours to attend a meeting. The return trip took only 4 hours because the speed was 5 miles per hour faster. What was the consultant's speed each way? \n" ); document.write( "
Algebra.Com's Answer #54990 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! A consultant traveled 5 hours to attend a meeting. The return trip took only 4 hours because the speed was 5 miles per hour faster. What was the consultant's speed each way? \n" ); document.write( "Distance = rate * time (d=rt) \n" ); document.write( "The distance is the same both ways so: \n" ); document.write( "rate to mtg* time to mtg= rate from mtg*time from mtg \n" ); document.write( "Let the rate to mtg be: r \n" ); document.write( "The time is:5 \n" ); document.write( "The distance to mtg is: 5r \n" ); document.write( "Then the rate from mtg is: r+5 \n" ); document.write( "The time from mtg is: 4 \n" ); document.write( "The distance from mtg is: 4(r+5)=4r+20 \n" ); document.write( "Problem to solve: \n" ); document.write( "5r=4r+20 \n" ); document.write( "5r-4r=4r-4r+20 \n" ); document.write( "r=20 \n" ); document.write( "The rate to mtg is: r=20 mph \n" ); document.write( "The rate from mtg is: r+5=20+5=25 mph \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |