document.write( "Question 76680: A consultant traveled 5 hours to attend a meeting. The return trip took only 4 hours because the speed was 5 miles per hour faster. What was the consultant's speed each way? \n" ); document.write( "
Algebra.Com's Answer #54990 by funmath(2933)\"\" \"About 
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A consultant traveled 5 hours to attend a meeting. The return trip took only 4 hours because the speed was 5 miles per hour faster. What was the consultant's speed each way?
\n" ); document.write( "Distance = rate * time (d=rt)
\n" ); document.write( "The distance is the same both ways so:
\n" ); document.write( "rate to mtg* time to mtg= rate from mtg*time from mtg
\n" ); document.write( "Let the rate to mtg be: r
\n" ); document.write( "The time is:5
\n" ); document.write( "The distance to mtg is: 5r
\n" ); document.write( "Then the rate from mtg is: r+5
\n" ); document.write( "The time from mtg is: 4
\n" ); document.write( "The distance from mtg is: 4(r+5)=4r+20
\n" ); document.write( "Problem to solve:
\n" ); document.write( "5r=4r+20
\n" ); document.write( "5r-4r=4r-4r+20
\n" ); document.write( "r=20
\n" ); document.write( "The rate to mtg is: r=20 mph
\n" ); document.write( "The rate from mtg is: r+5=20+5=25 mph
\n" ); document.write( "Happy Calculating!!!!
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