document.write( "Question 76678: Find the length of each side of the rectangle so that it has the given perimeter.
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document.write( "Note: Perimeter = 2*length + 2*width
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document.write( "Length= 2x-5
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document.write( "Width= x
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document.write( "p=50 in. \n" );
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Algebra.Com's Answer #54989 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Find the length of each side of the rectangle so that it has the given perimeter. \n" ); document.write( "Note: Perimeter = 2*length + 2*width \n" ); document.write( "Length= 2x-5 \n" ); document.write( "Width= x \n" ); document.write( " \n" ); document.write( "p=50 in. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Length=2x-5= 2(10)-5=20-5=15 in. \n" ); document.write( "Width=x=10 in \n" ); document.write( "Sanity check, does a rectangle with a length of 15 in and a width of 10 in have a peimeter that is 50 in? \n" ); document.write( "50=2(15)+2(10) \n" ); document.write( "50=30+20 \n" ); document.write( "50=50 \n" ); document.write( "We're not off our rocker!!!! \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |