document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906435>Question 906435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An isosceles right triangle has legs measuring (x-2) cm each. the hypotenuse has measure (x+4) cm. find x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549855 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An isosceles right triangle has legs measuring (x-2) cm each. the hypotenuse has measure (x+4) cm. find x<BR>\n" );
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document.write( "(x-2)^2 + (x-2)^2 = (x+4)^2<BR>\n" );
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document.write( "2[x^2-4x+4] = x^2 + 8x + 16<BR>\n" );
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document.write( "2x^2 - 8x + 8 = x^2 + 8x + 16<BR>\n" );
document.write( "x^2 - 16x - 8 = 0<BR>\n" );
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document.write( "x = [16 +- sqrt(16^2-4*-8)]/2<BR>\n" );
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document.write( "x = [16 +- sqrt(288)]/2<BR>\n" );
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document.write( "x = [16 +- 16.97]/2<BR>\n" );
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document.write( "x = 16.49 or x = -0.49<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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