document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=904251>Question 904251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation. <BR>\n" );
document.write( "Log(4p+1) + log(p) = log(3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549825 by </B><A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><B>AlgebraLady88(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=AlgebraLady88><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log ( 4p + 1) + log (p) = log (3)\r<BR>\n" );
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document.write( "Remember the log rule :\r<BR>\n" );
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document.write( "log x + log y = log xy\r<BR>\n" );
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document.write( "Therefore, log ( 4p +1) + log (p) = log (3)<BR>\n" );
document.write( "           log  p( 4p + 1) = log 3\r<BR>\n" );
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document.write( "When the bases are the same , then we can make p(4p+1) = 3\r<BR>\n" );
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document.write( "This will give us 4p^2 + p -3 =0<BR>\n" );
document.write( " which is (4p-3)(p+1) =0<BR>\n" );
document.write( "4p-3 =0      <BR>\n" );
document.write( "4p =3        <BR>\n" );
document.write( "p= 3/4    \r<BR>\n" );
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document.write( "p+1 =0<BR>\n" );
document.write( "p= -1\r<BR>\n" );
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document.write( "Since we cannot have a negative inside a logarithm, we can only take p= 3/4 as the answer.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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