document.write( "Question 906420: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t − 16t^2 . \r
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document.write( "The maximum height that the ball reaches is ____ feet \r
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document.write( "The ball reaches its maximum height when t = ____ seconds. \r
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document.write( "The ball hits the ground ____ seconds after it was thrown. \r
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document.write( "What is the average rate of change in the ball's height from t = a to t = a + h? (Don't forget to simplify Average rate of change = ____ feet/second \n" );
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Algebra.Com's Answer #549820 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! h(t) = 24t − 16t^2 \n" ); document.write( "-32t+24=0 \n" ); document.write( "4t=3 \n" ); document.write( "t=.75 sec at max h(t)=9 ft \n" ); document.write( "0= 24t − 16t^2\r \n" ); document.write( "\n" ); document.write( "24t = 16t^2 \n" ); document.write( "3t=2t^2 \n" ); document.write( "3=2t \n" ); document.write( "t=3/2 when it hits the ground\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |