document.write( "Question 76658: The profit on a watch is given by P = x^2 - 13x -80, where x is the number of watches sold per day. How many watches were sold on a day when there was a $50 loss?\r
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document.write( "Thanks so much for you help this one has me stummped. \n" );
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Algebra.Com's Answer #54982 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Where P = profit and x = the number of watches sold in a day. \n" ); document.write( ". \n" ); document.write( "If there was a $50 loss for the day, the profit was -50. Substitute this amount of profit \n" ); document.write( "into the equation and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Eliminate the -50 on the left side by adding +50 to both sides to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and reverse sides so that you have the equation in the standard quadratic form: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The left side of this equation can be factored to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this equation will be true if either of the factors are zero because multiplying \n" ); document.write( "anything by zero results in zero. \n" ); document.write( ". \n" ); document.write( "So solve for values of x that will make the left side zero by setting each factor, one \n" ); document.write( "at a time equal to zero. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We can reject the second solution because what does it mean to sell -2 watches ... buy 2 watches? \n" ); document.write( ". \n" ); document.write( "So the answer is that if you only sell 15 watches in a day, you lose $50. \n" ); document.write( ". \n" ); document.write( "And just for fun, let's get an idea of how many watches you need to sell daily to break even. \n" ); document.write( "You break even if your profit is zero, so we can write the equation: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you solve this using the quadratic formula (if you don't know this method yet, you \n" ); document.write( "probably will soon) you will find that the left side of this equation will be zero if \n" ); document.write( "x is equal to approximately 17.56 or if x = -4.56. Again we can ignore the negative \n" ); document.write( "solution. So this tells us that if 17 watches are sold in a day, you lose a little money \n" ); document.write( "and if 18 watches are sold, you make a little money. \n" ); document.write( ". \n" ); document.write( "Hope this analysis of the watch business gives you some insight into solving quadratic \n" ); document.write( "equations. A tricky part was to recognize that a negative profit is a loss, so you needed \n" ); document.write( "to substitute minus 50 dollars for the profit and then solve the equation for x. \n" ); document.write( " \n" ); document.write( " |