document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905881>Question 905881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> taninverse root 3-cotinverse minus root 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549801 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taninverse root 3-cotinverse minus root 3<BR>\n" );
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document.write( "The angle whose tangent is sqrt(3) is pi pi/3 or 60 degrees<BR>\n" );
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document.write( "the angle whose cotangent is -sqrt(3)is (5/6)pi or 150 degrees<BR>\n" );
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document.write( "Ans: pi/3 - (5/6)pi = (2/6 - 5/6)pi = -3/6 pi = -pi/2<BR>\n" );
document.write( "or 60 = 150 = -90<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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