document.write( "Question 10329: Solve the following:\r
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\n" ); document.write( "\n" ); document.write( "I = E/R + r for r\r
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\n" ); document.write( "\n" ); document.write( "I understand how to do this if there was not a \"+ r\" in the equation, but I am lost when it comes to the \"+ r\". I don't know what you do with it. I think it would turn into a \"1r\". \r
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\n" ); document.write( "\n" ); document.write( "I = E/r, then multiply both sides by r,and end up with the answer: E/I = r?\r
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\n" ); document.write( "\n" ); document.write( "Please let me know if this is correct, of if I am at least on the right track. Thanks for your help.
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Algebra.Com's Answer #5498 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Do you mean \"I+=+E%2F%28R+%2B+r%29\", solve for r?? If this is what you meant, then you needed parentheses around the (R+r). If that is NOT what you meant, then the solution is quite different from what I am about to do--resubmit the problem, we'll take another look at it. Also, remember that
\n" ); document.write( "in math, capital R and lower case r are considered two different variables!\r
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\n" ); document.write( "\n" ); document.write( "Assuming this is the problem you had in mind:
\n" ); document.write( "\"I%2F1+=+E%2F%28R%2Br%29+\". Remember \"a%2Fb=c%2Fd\"? It means \"ad=+bc\".\r
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\n" ); document.write( "\n" ); document.write( "In the same way, \"I%2F1+=+E%2F%28R%2Br%29+\" means that
\n" ); document.write( "\"I%2A%28R%2Br%29+=+1%2AE\"\r
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\n" ); document.write( "\n" ); document.write( "Remove parentheses:
\n" ); document.write( "IR + Ir = E\r
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\n" ); document.write( "\n" ); document.write( "Get the small r term all alone on the left side by subtracting IR from each side:
\n" ); document.write( "IR - IR + Ir = E - IR
\n" ); document.write( "Ir = E-IR\r
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\n" ); document.write( "\n" ); document.write( "Last, divide both sides by I:
\n" ); document.write( "\"+%28Ir%29%2FI+=+%28E-IR%29%2FI+\"
\n" ); document.write( "\"+r+=+%28E-IR%29%2FI+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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