document.write( "Question 906375: The radiator in a car is filled with a solution of 65% antifreeze and 35% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 4.3 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50%?
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document.write( "please please help me! \n" );
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Algebra.Com's Answer #549771 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 0.65*4.3-0.65x+0x=0.5(4.3) \n" ); document.write( "2.795+-0.65x=2.15 \n" ); document.write( "-0.65x=2.15-2.795 \n" ); document.write( "-0.65x=-0.645 \n" ); document.write( "x=0.99230769 liters means almost a liter \n" ); document.write( "check \n" ); document.write( "0.65*3.30769231+0*0.99230769=0.5(4.3) \n" ); document.write( "2.15+0.0=2.15 \n" ); document.write( "2.15=2.15 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |