document.write( "Question 906306: Write an equation in slope-intercept form for the line form that is perpendicular to 5x + 3y = 18 and passes through the origin. \n" ); document.write( "

Algebra.Com's Answer #549712 by ewatrrr(24785) $\"\"$ $\"About$

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the standard slope-intercept form for an equation of a line is
\n" ); document.write( " $\"y+=+highlight_green%28m%29x+%2B+highlight%28b%29\"$ where m is the slope and b the y-intercept.
\n" ); document.write( "5x + 3y = 18 0r y = (-5/3)x + 6, m = (-5/3)
\n" ); document.write( "New line: m = $\"++highlight_green%283%2F5%29+\"$ as $\"%28-5%2F3%29%283%2F5%29+=+-1\"$ (I think of 3/5 as the negative reciprocal of -5/3)
\n" ); document.write( "***Using point-slope form, $\"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"$ P(0,0)
\n" ); document.write( "y-0 = (3/5)(x-0)
\n" ); document.write( "y = (3/5)x in slope-intercept form \n" ); document.write( "

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