document.write( "Question 906208: a random sample of 88 observations produced a mean x = 25.8 and standard deviation s=2.7. Find 95%, 90% and 99% confidence interval for u\r
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Algebra.Com's Answer #549682 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
ME= 1.96(2.7/sqrt(88))
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\n" ); document.write( "ME= 1.645(2.7/sqrt(88))
\n" ); document.write( "CI: 25.8 - ME < \"mu\" < 25.8 + ME
\n" ); document.write( "ME= 2.576(2.7/sqrt(88))
\n" ); document.write( "CI: 25.8 - ME < \"mu\" < 25.8 + ME
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