document.write( "Question 76648: can you teach me how to do a rational equation and check it?\r
\n" ); document.write( "\n" ); document.write( "x/6-x/8=1
\n" ); document.write( "

Algebra.Com's Answer #54968 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( ".
\n" ); document.write( "\"%28x%2F6%29-%28x%2F8%29+=+1\"
\n" ); document.write( ".
\n" ); document.write( "You can get rid of both denominators by multiplying all the terms on both sides of the equation
\n" ); document.write( "by one of two methods. You can either first multiply the entire equation first by 6 and next
\n" ); document.write( "by 8 or you can multiply the entire equation by 48, the product of 6*8.
\n" ); document.write( ".
\n" ); document.write( "Let's do it in two stages. First multiply by 6 to get:
\n" ); document.write( ".
\n" ); document.write( "\"%286%2Ax%2F6%29+-+%286%2Ax%2F8%29+=+6%2A1\"
\n" ); document.write( ".
\n" ); document.write( "Then multiply this equation by 8 to get:
\n" ); document.write( ".
\n" ); document.write( "\"%288%2A6%2Ax%2F6%29+-+%288%2A6%2Ax%2F8%29+=+8%2A6%2A1\"
\n" ); document.write( ".
\n" ); document.write( "At this point you are at the same place that you would have been if you had just multiplied
\n" ); document.write( "the entire equation by 48 ... the product of the denominators.
\n" ); document.write( ".
\n" ); document.write( "Now, where you have the same term in the denominator and the numerator, you can cancel them
\n" ); document.write( "out as follows:
\n" ); document.write( ".
\n" ); document.write( "\"8%2Across%286%29%2Ax%2Fcross%286%29+-+cross%288%29%2A6%2Ax%2Fcross%288%29+=+8%2A6%2A1\"
\n" ); document.write( ".
\n" ); document.write( "This leaves you with:
\n" ); document.write( ".
\n" ); document.write( "\"%288%2Ax%29+-+6%2Ax+=+48\"
\n" ); document.write( ".
\n" ); document.write( "Notice that I multiplied out the right side. Now you can combine the two terms on the
\n" ); document.write( "left side to get:
\n" ); document.write( ".
\n" ); document.write( "\"2x+=+48\"
\n" ); document.write( ".
\n" ); document.write( "and this can be solved by dividing both the left and right side by 2 to get:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+48%2F2+=+24\"
\n" ); document.write( ".
\n" ); document.write( "Check this by going back to the original problem:
\n" ); document.write( ".
\n" ); document.write( "\"%28x%2F6%29-%28x%2F8%29+=+1\"
\n" ); document.write( ".
\n" ); document.write( "Now substitute 24 for x and you get:
\n" ); document.write( ".
\n" ); document.write( "\"%2824%2F6%29-%2824%2F8%29+=+1\"
\n" ); document.write( ".
\n" ); document.write( "But 24 divided by 6 is 4 and 24 divided by 8 is 3. Substitute these values and the equation
\n" ); document.write( "becomes:
\n" ); document.write( ".
\n" ); document.write( "\"4+-+3+=+1\"
\n" ); document.write( ".
\n" ); document.write( "And obviously the left side equals the right side. So our answer of \"x+=+24\" is correct.
\n" ); document.write( ".
\n" ); document.write( "You can use this method to get rid of the denominators, and then you are working with an
\n" ); document.write( "ordinary old algebraic equation ... which is a lot easier than trying to mess around with
\n" ); document.write( "fractions. Hope this helps you to understand a method of solving an equation like this
\n" ); document.write( "one.
\n" ); document.write( "
\n" );