document.write( "Question 76645: Will someone please help me with this problem?A stockbroker has money in three accounts. The interest rates on the three accounts are 9%, 10%, and 11%. If she has twice as much money invested at 10% as she has invested at 9%, three times as much at 11% as she has at 9%, and the total interest for the year is $930, how much money is invested at each rate? Enter your answer in the form without the units. Let be the amount of money invested at 9%, be the amount of money invested at 10%, and be the amount of money invested at 11%.
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document.write( "Thank You,
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document.write( "Sabrina \r
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Algebra.Com's Answer #54967 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! I'm not sure what the last sentence in your problem is supposed to mean. But let's work \n" ); document.write( "the problem based on the preceding givens. First let's say that N is the amount that she has \n" ); document.write( "invested at 9% (or in decimal form 0.09). Then let's say that T is the amount that she \n" ); document.write( "has invested at 10% (or in decimal form 0.10). Finally, let's say that E is the amount that \n" ); document.write( "she has invested at 11% (or in decimal form 0.11). \n" ); document.write( ". \n" ); document.write( "The problem says that the money invested at 10% is twice the amount invested at 9%. So we \n" ); document.write( "can say that T = 2*N. And it also says that the money invested at 11% is three times the \n" ); document.write( "amount invested at 9%. So we can say that E = 3*N. \n" ); document.write( ". \n" ); document.write( "The next thing we know is that the sum of all the interest earned for the year is $930. \n" ); document.write( "And we know that interest is computed by multiplying the rate times the corresponding \n" ); document.write( "amount that is invested at that rate. So we can write that the total interest is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then since we know that T = 2*N and E = 3*N, we can substitute 2*N for T and 3*N for E to \n" ); document.write( "change the equation to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Do the multiplications on the left side to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add all the terms on the left side and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally solve for N by dividing both sides by 0.62 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The amount invested at 9% is $1,500. Twice as much, or $3,000, is invested at 10% and \n" ); document.write( "three times as much, or $4,500, is invested at 11%. \n" ); document.write( ". \n" ); document.write( "Hope this gives you some insight into how to do this problem. Remember that to calculate \n" ); document.write( "the amount of interest you multiply the amount invested by the rate of interest that it \n" ); document.write( "earns. \n" ); document.write( " |