document.write( "Question 906157: The effectiveness of a television commercial depends on how many times a viewer watches it. After some experiments an advertising agency found that if the effectiveness E is measured on a scale of 0 to 10, then \r
\n" ); document.write( "\n" ); document.write( "E(n) = \"+%282%2F3%29n+-+160n%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "A beter view: http://i.imgur.com/kG6LIka.png\r
\n" ); document.write( "\n" ); document.write( "where n is the number of times a viewer watches a given commercial. For a commercial to have maximum effectiveness, how many times should a viewer watch it? ____ times
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Algebra.Com's Answer #549656 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
as I can see on image, you have this\r
\n" ); document.write( "\n" ); document.write( "\"E%28n%29+=++%282%2F3%29n+-+%281%2F60%29n%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "For this problem, E(n) is a function of n. We're trying to find the maximum value of E(n). \r
\n" ); document.write( "\n" ); document.write( " Assuming this is for a pre-calculus or calculus course, they probably want you to take the derivative. \r
\n" ); document.write( "\n" ); document.write( " So the derivative is:
\n" ); document.write( " E'\"%28n%29+=+2%2F3+-+%281%2F60%29n\"\r
\n" ); document.write( "\n" ); document.write( " The maximum then occurs when \"2%2F3+-+%281%2F60%29+n+=+0\".
\n" ); document.write( " So \"+%281%2F60%29+n+=+2%2F3\", and \"n+=%282%2F3%29%2F%281%2F60%29=+120%2F3\" or \"n+=+40\".
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