document.write( "Question 906155: Could you please show me how to prove the following identities...
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document.write( "A) cos2x=2cos^2x-1
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document.write( "B) cos2x=1-2sin^2x
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document.write( "C) (1/1+sinx)+(1/1-sinx)=2sec^2x \n" );
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Algebra.Com's Answer #549652 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! prove the following identities... \n" ); document.write( "A) cos2x=2cos^2x-1 \n" ); document.write( "start with left side: \n" ); document.write( "cos2x=cos(x+x) \n" ); document.write( "=coscosx-sinxsinx \n" ); document.write( "=cos^2x-(1-cos^2x)=2cos^x-1 \n" ); document.write( "verified: left side=right side \n" ); document.write( ".. \n" ); document.write( "B) cos2x=1-2sin^2x \n" ); document.write( "start with left side: \n" ); document.write( "cos2x=cos(x+x) \n" ); document.write( "=coscosx-sinxsinx \n" ); document.write( "=cos^2x-sin^2x=1-sin^2x-sin^2x \n" ); document.write( "=1-2sin^2x \n" ); document.write( "verified: left side=right side \n" ); document.write( ".. \n" ); document.write( "C) (1/1+sinx)+(1/1-sinx)=2sec^2x \n" ); document.write( "start with left side: \n" ); document.write( "(1/1+sinx)+(1/1-sinx) \n" ); document.write( "=(1-sinx+1+sinx)/(1+sinx)(1-sinx) \n" ); document.write( "=2/1-sin^2x \n" ); document.write( "=2/cos^2x \n" ); document.write( "=2sec^2x \n" ); document.write( "verified: left side=right side \n" ); document.write( " |