document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906152>Question 906152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given AC=AB+AB prove AB=BC A----B----C please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549647 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AC=AB+AB\r<BR>\n" );
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document.write( "AC=2*AB\r<BR>\n" );
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document.write( "Which implies that 2 copies of AB are needed to construct AC. Since AB + BC = AC, this must mean that BC = AB or AB = BC\r<BR>\n" );
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document.write( "Think about it in reverse: say we know that AB = BC and AB + BC = AC\r<BR>\n" );
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document.write( "we can replace BC with AB to get \r<BR>\n" );
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document.write( "AB + BC = AC\r<BR>\n" );
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document.write( "AB + AB = AC\r<BR>\n" );
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document.write( "AC = AB + AB\r<BR>\n" );
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document.write( "which is what we start with </SPAN>\n" );
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