document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76624>Question 76624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> passes through (1,4) and is parallel to a line whose equation is y=3x+5?\r<BR>\n" );
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document.write( "my start:  4=3x+5<BR>\n" );
document.write( "           4=3(1)+5<BR>\n" );
document.write( "          -3+4=-3+3+5<BR>\n" );
document.write( "           1=x+5 ?????<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54962 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you've got the right idea, but a parallel line will have a different y-intercept (the constant term on the x side of the equation)\r<BR>\n" );
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document.write( "general form is y=mx+b...m is slope (same for parallel lines)...b is y-intercept (where line crosses y-axis)\r<BR>\n" );
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document.write( "your start has the slope the same but also the intercept... try 4=3x+b...then 4=3(1)+b...so b=1\r<BR>\n" );
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document.write( "y=3x+1...new line is parallel to old line and crosses y-axis 4 units lower </SPAN>\n" );
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