document.write( "Question 76611: can you help me solve this problem\r
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document.write( "square root of 2x + 8 - square root of 2x + 1 = 1 \n" );
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Algebra.Com's Answer #54961 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! : \n" ); document.write( "square root of 2x + 8 - square root of 2x + 1 = 1 \n" ); document.write( "Here it is step-by-step \n" ); document.write( ": \n" ); document.write( "Sqrt(2x+8) - Sqrt(2x+1) = 1 \n" ); document.write( ": \n" ); document.write( "Sqrt(2x+8) = Sqrt(2x+1) + 1; added Sqrt(2x+1) to both sides \n" ); document.write( ": \n" ); document.write( "Square both sides, gets rid of the radical on the left: \n" ); document.write( "FOIL (Sqrt(2x+1)+ 1)*(Sqrt(2x+1) + 1) on the right \n" ); document.write( ": \n" ); document.write( "2x + 8 = (2x+1) + 2Sqrt(2x+1) + 1 \n" ); document.write( ": \n" ); document.write( "2x + 8 = 2x + 1 + 1 + 2Sqrt(2x+1) \n" ); document.write( "2x + 8 = 2x + 2 + 2Sqrt(2x+1) \n" ); document.write( ": \n" ); document.write( "Subtract 2x and 2 from both sides, isolates the radical on the right \n" ); document.write( "2x - 2x + 8 - 2 = 2Sqrt(2x+1) \n" ); document.write( "6 = 2Sqrt(2x + 1) \n" ); document.write( "; \n" ); document.write( "Square both sides, gets rid of the 2nd radical, you have: \n" ); document.write( "36 = 4(2x + 1) \n" ); document.write( "36 = 8x + 4; multiplied what's inside the brackets \n" ); document.write( "36 - 4 = 8x: subtract 4 from both sides \n" ); document.write( "32 = 8x \n" ); document.write( "x = 32/8 \n" ); document.write( "x = 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation: \n" ); document.write( "Sqrt(2(4) + 8) - Sqrt(2(4) + 1) = 1 \n" ); document.write( "Sqrt(8 + 8) - Sqrt(8 + 1) = 1 \n" ); document.write( "Sqrt(16) - Sqrt(9) = 1; proves our solution is correct \n" ); document.write( ": \n" ); document.write( "How about this, do you have an idea of how to do these now? \n" ); document.write( " \n" ); document.write( " |