document.write( "Question 76611: can you help me solve this problem\r
\n" ); document.write( "\n" ); document.write( "square root of 2x + 8 - square root of 2x + 1 = 1
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Algebra.Com's Answer #54961 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
:
\n" ); document.write( "square root of 2x + 8 - square root of 2x + 1 = 1
\n" ); document.write( "Here it is step-by-step
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\n" ); document.write( "Sqrt(2x+8) - Sqrt(2x+1) = 1
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\n" ); document.write( "Sqrt(2x+8) = Sqrt(2x+1) + 1; added Sqrt(2x+1) to both sides
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\n" ); document.write( "Square both sides, gets rid of the radical on the left:
\n" ); document.write( "FOIL (Sqrt(2x+1)+ 1)*(Sqrt(2x+1) + 1) on the right
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\n" ); document.write( "2x + 8 = (2x+1) + 2Sqrt(2x+1) + 1
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\n" ); document.write( "2x + 8 = 2x + 1 + 1 + 2Sqrt(2x+1)
\n" ); document.write( "2x + 8 = 2x + 2 + 2Sqrt(2x+1)
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\n" ); document.write( "Subtract 2x and 2 from both sides, isolates the radical on the right
\n" ); document.write( "2x - 2x + 8 - 2 = 2Sqrt(2x+1)
\n" ); document.write( "6 = 2Sqrt(2x + 1)
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\n" ); document.write( "Square both sides, gets rid of the 2nd radical, you have:
\n" ); document.write( "36 = 4(2x + 1)
\n" ); document.write( "36 = 8x + 4; multiplied what's inside the brackets
\n" ); document.write( "36 - 4 = 8x: subtract 4 from both sides
\n" ); document.write( "32 = 8x
\n" ); document.write( "x = 32/8
\n" ); document.write( "x = 4
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "Sqrt(2(4) + 8) - Sqrt(2(4) + 1) = 1
\n" ); document.write( "Sqrt(8 + 8) - Sqrt(8 + 1) = 1
\n" ); document.write( "Sqrt(16) - Sqrt(9) = 1; proves our solution is correct
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\n" ); document.write( "How about this, do you have an idea of how to do these now?
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