document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906038>Question 906038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It asks me find the equation that is parallel to y=-5 and passes through (-3,5). Am not sure how to start this equation off, either with point slope form or some other formula I can't remember </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549608 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It asks me find the equation that is parallel to y=-5 and passes through (-3,5).<BR>\n" );
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document.write( "y=-5 is an equation of a horizontal line(slope=0)where y=-5 for all values of x<BR>\n" );
document.write( "y=5 is also a horizontal line like equation of given line except y=5 for all values of x. It must, therefore, be parallel to given line and pass through (-3,5) </SPAN>\n" );
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