document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76618>Question 76618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jake's bratwurst stand sells three times as many bratwursts as Lisa's stand. The difference between their sales is 400 bratwursts.  How many bratwursts did Jake sell? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54955 by </B><A HREF=/tutors/aboutme.mpl?userid=stargrl12566><B>stargrl12566(16)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stargrl12566><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a substitution problem once you get the equations. <BR>\n" );
document.write( "The two equations are, when j=jake and l=lisa<BR>\n" );
document.write( "3l=j<BR>\n" );
document.write( "j-l=400<BR>\n" );
document.write( "you substitute the \"j\" in the second equation the the first equation.<BR>\n" );
document.write( "so you get 3l-l=400.<BR>\n" );
document.write( "then you solve the simple algebraic equation to get l=200.<BR>\n" );
document.write( "then to get how many jake sells, you plug in what l equals into either equation.<BR>\n" );
document.write( "3(200)=j<BR>\n" );
document.write( "j=600  </SPAN>\n" );
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