document.write( "Question 905901: 17,818 is invested, part at 11% and the rest at 6%. if the interest earned from the amount invested at 11% exceeds the interest earned from the amount invested at 6% by 490.33, how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #549548 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
We know the total amount of money invested. $17818
\n" ); document.write( "x+y=17818,
\n" ); document.write( "We know that the difference in interest earned by the two accounts is $490.33
\n" ); document.write( "0.11*x-0.06*y=490.33
\n" ); document.write( "x=17818-y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.11*(17818-y)-0.06*y=490.33
\n" ); document.write( "We multiply out
\n" ); document.write( "1959.98-0.11y-0.06*y=490.33
\n" ); document.write( "We combine like terms.
\n" ); document.write( "1469.65=0.17*y
\n" ); document.write( "Isolate y
\n" ); document.write( "y=1469.65/0.17\r
\n" ); document.write( "\n" ); document.write( "y=8645 at 6%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=17818-8645
\n" ); document.write( "x=9173 at 11%
\n" ); document.write( "Check
\n" ); document.write( "0.11*9173-0.06*8645=490.33
\n" ); document.write( "interest earned at 11%=1009.03
\n" ); document.write( "interest earned at 6%=518.70
\n" ); document.write( "1009.03-518.7=490.33
\n" ); document.write( "490.33=490.33
\n" ); document.write( "Since this statement is TRUE and neither amount is negative then all is well.
\n" ); document.write( " \n" ); document.write( "
\n" );