document.write( "Question 905950: Find the minimum sample size that should be chosen to assure that the proportion estimate p will be within the required margin of error, .06. Use a 95% confidence interval and a population proportion of .7. The critical value for a 95% confidence level is 1.96 \n" ); document.write( "
Algebra.Com's Answer #549539 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You may use Your TI (or any other calculator for the Arithmetic...) \n" ); document.write( "this one is a need to know: ME = \n" ); document.write( "ME = .07 = 1.96sqrt(.7*.3/n) \n" ); document.write( " (.07/1.96)^2 = .21/n \n" ); document.write( "n = .21/(.07/1.96)^2 = 164.64 0r 165 (always round Up for number of people) \n" ); document.write( " |