document.write( "Question 905949: The area of a rectangle is 55 yd2, and the length of the rectangle is 4 yd less than three times the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #549536 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
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\n" ); document.write( "A = (3w-4)w = 55yd^2
\n" ); document.write( "3w^2 -4w - 55 = 0
\n" ); document.write( "(3w +11)(w -5) =0
\n" ); document.write( "w = 5yd and L = 11yd \"3%2A5-4\"
\n" ); document.write( "and..checking
\n" ); document.write( "A = 55yd^2
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