document.write( "Question 905924: printing machine A can do printing in 8 hours. With the machine B the same printing would take 12 hours. It was decided that both machines will be used for the printing. However, after a while the machine A broke down. After that it took 6 hours to finish the printing with machine B. How many hours did the machine A print before it broke down? \n" ); document.write( "
Algebra.Com's Answer #549511 by josgarithmetic(39616)\"\" \"About 
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RATES JOB/HOUR
\n" ); document.write( "Machine A, \"1%2F8\"
\n" ); document.write( "Machine B, \"1%2F12\"
\n" ); document.write( "CombinedAB, \"1%2F8%2B1%2F12=3%2F24%2B2%2F24=5%2F24\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "RT=J Uniform Rate rule for doing a job\r
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\n" ); document.write( "\n" ); document.write( "The job is split into two time quantities. The combined machines part for unknown t time and then the machine B part which was 6 hours.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28%285%2F24%29%2At%2B%281%2F12%29%2A6=1%29\", doing ONE job.
\n" ); document.write( "\"%285%2F24%29t%2B%281%2F2%29=1\"
\n" ); document.write( "\"%285%2F24%29t=1%2F2\"
\n" ); document.write( "\"t=24%2F%285%2A2%29\"
\n" ); document.write( "\"t=12%2F5\"
\n" ); document.write( "\"highlight%28t=2%262%2F5%29\"
\n" ); document.write( "2 hours 24 minutes, time that A and B worked together before A quit.
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