document.write( "Question 76586: Can you help me simplify 2+3i/8i
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Algebra.Com's Answer #54951 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Can you help me simplify \"%28%282%2B3i%29%29%2F%288i%29\"
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\n" ); document.write( "Any expression over itself = 1 so we can multiply it by \"%288i%29%2F%288i%29\"
\n" ); document.write( "without changing it's value, but it gets rid of i in the denominator
\n" ); document.write( "Remember i^2 = -1
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\n" ); document.write( "\"%28%282%2B3i%29%29%2F%288i%29\" * \"%288i%29%2F%288i%29\" = \"%28%2816i+%2B+24%28i%5E2%29%29%29%2F%2864%28i%5E2%29%29\" = \"%28%2816i+%2B+24%28-1%29%29%29%2F%2864%28-1%29%29\" = \"%28%2816i+-+24%29%29%2F%28-64%29\"
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\n" ); document.write( "Divide the numerator and the denominators by 8, (reduces the fractions)
\n" ); document.write( "\"-%28%282i+-+3%29%29%2F%288%29\" = \"%28%283-2i%29%29%2F%288%29\"
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