document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905908>Question 905908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width.\r<BR>\n" );
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document.write( "Find the length and width of the rectangle described. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549486 by </B><A HREF=/tutors/aboutme.mpl?userid=100601><B>100601(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=100601><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l= length in cm<BR>\n" );
document.write( "w= width in cm<BR>\n" );
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document.write( "Keep in mind that you can substitute = for the word 'is' in word problems.<BR>\n" );
document.write( "l=3w-4<BR>\n" );
document.write( "Perimeter=2w+22<BR>\n" );
document.write( "Perimeter=2l+2w<BR>\n" );
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document.write( "Substitute 2l+2w for the perimeter<BR>\n" );
document.write( "2l+2w=2w+22<BR>\n" );
document.write( "2l=22<BR>\n" );
document.write( "l=11<BR>\n" );
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document.write( "Now find w by substitute 11 for l in the first equation.<BR>\n" );
document.write( "11=3w-4<BR>\n" );
document.write( "3w=15<BR>\n" );
document.write( "w=5<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "length- 11 cm<BR>\n" );
document.write( "width- 5 cm<BR>\n" );
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