document.write( "Question 905890: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps!
\n" ); document.write( "Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Christopher. If the sum off all of their ages is 66, how old is Christopher?
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Algebra.Com's Answer #549482 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"A=3B\"
\n" ); document.write( "\"B=%285%2F2%29C\"
\n" ); document.write( "\"A%2BB%2BC=66\"
\n" ); document.write( "From eq. 2,
\n" ); document.write( "\"C=%282%2F5%29B\"
\n" ); document.write( "Substitute,
\n" ); document.write( "\"3B%2BB%2B%282%2F5%29B=66\"
\n" ); document.write( "\"%2815%2F5%2B5%2F5%2B2%2F5%29B=66\"
\n" ); document.write( "\"%2822%2F5%29B=66\"
\n" ); document.write( "\"B=15\"
\n" ); document.write( "Now that you know Bailey's age, work backwards to find Addison and Christopher's ages.
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