document.write( "Question 905890: I am having trouble figuring out how to set up this problem. Thank you in advance to anyone who helps!
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document.write( "Addison is 3 times as old as Bailey and Bailey is 2.5 times as old as Christopher. If the sum off all of their ages is 66, how old is Christopher? \n" );
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Algebra.Com's Answer #549482 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "From eq. 2, \n" ); document.write( " \n" ); document.write( "Substitute, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now that you know Bailey's age, work backwards to find Addison and Christopher's ages. \n" ); document.write( " |