document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905889>Question 905889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could someone please help me with the following question. <BR>\n" );
document.write( "A formula is given as V=2u+3tē. Change the subject of the formula to t. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549473 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you want to solve for t instead of v.\r<BR>\n" );
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document.write( "the original equation is:\r<BR>\n" );
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document.write( "v = 2u + 3t^2\r<BR>\n" );
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document.write( "subtract 3t^2 from both sides of the equation and subtract v from both sides of the equation to get:\r<BR>\n" );
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document.write( "-3t^2 = 2u - v\r<BR>\n" );
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document.write( "divide both sides of the equation by -3 to get:\r<BR>\n" );
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document.write( "t^2 = 2u/-3 - v/-3\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "t^2 = -2u/3 + v/3\r<BR>\n" );
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document.write( "simplify further to get t^2 = (-2u+v)/3\r<BR>\n" );
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document.write( "take the square root of both sides of the equation to get:\r<BR>\n" );
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document.write( "t = plus or minus sqrt((-2u+v)/3)\r<BR>\n" );
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document.write( "problem is now solved for t instead of v.\r<BR>\n" );
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document.write( "you can confirm you did it correctly by seeing that both equations are compatible with each other.\r<BR>\n" );
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document.write( "here's what i did:\r<BR>\n" );
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document.write( "start with t = plus or minus sqrt((-2u+v)/3)\r<BR>\n" );
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document.write( "let v = 400 and let u = 50 and solve for t.<BR>\n" );
document.write( "these numbers were chosen so that the solutions would be integers.\r<BR>\n" );
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document.write( "you get t = plus or minus 10\r<BR>\n" );
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document.write( "now start with v = 2u + 3t^2 (your original equation)\r<BR>\n" );
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document.write( "let u = 50 and t = plus or minus 10.\r<BR>\n" );
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document.write( "when t = 10, you get v = 100 + 3*100 = 400\r<BR>\n" );
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document.write( "when t = -10, you get v = 100 + 3*100 = 400\r<BR>\n" );
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document.write( "the two equations are compatible with each other which confirms that you did the translation from solving for v to solving for t successfully.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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