document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905849>Question 905849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 80 and their difference is half their addition. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549446 by </B><A HREF=/tutors/aboutme.mpl?userid=100601><B>100601(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=100601><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the numbers for x and y. This will be a system of equations, which means that there will be two or more equations.\r<BR>\n" );
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document.write( "x= one of the numbers<BR>\n" );
document.write( "y= one of the numbers\r<BR>\n" );
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document.write( "x+y= 80<BR>\n" );
document.write( "x-y=1/2(x+y)\r<BR>\n" );
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document.write( "Substitute x+y for 80.<BR>\n" );
document.write( "x-y=1/2(80)<BR>\n" );
document.write( "x-y=40\r<BR>\n" );
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document.write( "Now that you've simplified the equation, here are the two equations:<BR>\n" );
document.write( "x+y=80<BR>\n" );
document.write( "x-y=40\r<BR>\n" );
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document.write( "You can subtract the two equations from each other:<BR>\n" );
document.write( "  (x+y=80)<BR>\n" );
document.write( "- (x-y=40)<BR>\n" );
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document.write( "     2y=40<BR>\n" );
document.write( "      y=20\r<BR>\n" );
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document.write( "Because y=20, x=60 since y+x=80. </SPAN>\n" );
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