document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905815>Question 905815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> is it possible to draw a polygon that has interior angles that sum up to 1300\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549424 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No, the sum is always an integral multiple of 180 degrees.<BR>\n" );
document.write( "If n = # of angles (also the # of sides),<BR>\n" );
document.write( "Sum = (n-2)*180, n = 3,4,5 ...<BR>\n" );
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document.write( "The minimum value of n = 3.  No polygon has fewer than 3 sides.<BR>\n" );
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document.write( "Don't try the old joke, \"How many sides does a circle have?\"  Answer: 2, inside and outside. </SPAN>\n" );
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