document.write( "Question 905576: you are walking from your physics class at a speed of 1.0 m/s. your friend leaves two minutes later at the rate of 1.3 m/s. how long will it take you friend to catch up to you? \n" ); document.write( "
Algebra.Com's Answer #549407 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Gaining speed 1.3 -1= 0.3 m/s \n" ); document.write( "Headstart 1*120 =120 meters \n" ); document.write( "Time to catch up 120/0.3=400.0 sec \n" ); document.write( "Algebraic solution \n" ); document.write( "1(t+120)=1.3t \n" ); document.write( "1t+120=1.3t \n" ); document.write( "120=1.3t-1t \n" ); document.write( "120=0.3t \n" ); document.write( "t=400.0 sec \n" ); document.write( "t=400/60=6 2/3 minutes \n" ); document.write( "Distance to meeting 400.0*1.3=520 meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |