document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905595>Question 905595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sally and betty are both leaving the grocery store to go to Sally's house.  Sally leaves 40 seconds before betty.  Sally travels on her bike at a pace of 8 feet per second.  Betty travels at a pace of 12 feet per second.  At what time will Sally and Betty be the same distance from the grocery store.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549405 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 12 -8= 4f/s<BR>\n" );
document.write( "Headstart 8*40 =320 ft<BR>\n" );
document.write( "Time to catch up 320/4=80 sec<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "8(t+40)=12t<BR>\n" );
document.write( "8t+320=12t<BR>\n" );
document.write( "320=12t-8t<BR>\n" );
document.write( "320=4t<BR>\n" );
document.write( "t=80  sec<BR>\n" );
document.write( "Distance to meeting 80*12=960 ft<BR>\n" );
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