document.write( "Question 905586: how much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 15% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #549379 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
from view of antifreeze
\n" ); document.write( "1*1=0.15*(1+x)
\n" ); document.write( "1=0.15+0.15*x
\n" ); document.write( "1-0.15=0.15*x
\n" ); document.write( "0.85=0.15*x
\n" ); document.write( "x=5.66666667
\n" ); document.write( "check
\n" ); document.write( "1*1=0.15*(1+x)
\n" ); document.write( "1*1=0.15*(6.66666667)
\n" ); document.write( "1=1.0
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "or from view of water
\n" ); document.write( "1*y+0*1=0.85(1+y)
\n" ); document.write( "1*y+0=0.85+0.85y
\n" ); document.write( "1*y-0.85y=0.85-0
\n" ); document.write( "0.15y=0.85
\n" ); document.write( "y=0.85/0.15
\n" ); document.write( "y=5.66666667
\n" ); document.write( "acid view x 5.66666667= water view y 5.66666667
\n" ); document.write( "match 5.66666667=5.66666667
\n" ); document.write( " \n" ); document.write( "
\n" );