document.write( "Question 849: the base of a triangle is (2x+3) feet long and the height is (x+3) feet long. If the area of the triangle is 27 square feet, find the base and height of the triangle. \n" ); document.write( "
Algebra.Com's Answer #549365 by ritupuneet(1)\"\" \"About 
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As we know the formula of area of triangle is\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2*base*height ------(1)
\n" ); document.write( "base =(2x+3)
\n" ); document.write( "height=(x+3)
\n" ); document.write( "Area = 27
\n" ); document.write( "Put the value in equation (1)\r
\n" ); document.write( "\n" ); document.write( "27 = 1/2*(2x+3)(x+3)
\n" ); document.write( "27*2 = (2x+3)x+(2x+3)3
\n" ); document.write( "54 = 2x^2+3x+6x+9
\n" ); document.write( "54 = 2x^2+9x+9
\n" ); document.write( "2x^2+9x+9-54 = 0
\n" ); document.write( "2x^2+9x-45=0
\n" ); document.write( "by factorization we can write the equation
\n" ); document.write( "2x^2+(15-6)x-45=0
\n" ); document.write( "2x^2+15x-6x-45=0
\n" ); document.write( "x(2x+15)-3(2x+15)=0
\n" ); document.write( "(2x+15)(x-3)=0
\n" ); document.write( "x=0,-15/2
\n" ); document.write( "Ignore the negative value\r
\n" ); document.write( "\n" ); document.write( "Base =2x+3 = 2*3+3 = 9
\n" ); document.write( "Height = x+3 = 3+3 6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so Base is 9 & Height is 6
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