document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905648>Question 905648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Over the weekend, Juan bicycled 49 miles. On Sunday he rode 10 miles more than one-half of his distance on Saturday. Find the number of miles he rode each day. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549364 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let N be Sunday, and S represent Saturday.<BR>\n" );
document.write( "S + N = 49<BR>\n" );
document.write( "N = .5S + 10<BR>\n" );
document.write( "Take the value of N from the second equation and put it into the first.<BR>\n" );
document.write( "S + N = 49<BR>\n" );
document.write( "S + (.5S+10) = 49<BR>\n" );
document.write( "1.5S + 10 = 49<BR>\n" );
document.write( "Subtract 10 from each side<BR>\n" );
document.write( "1.5S = 39<BR>\n" );
document.write( "Divide each side by 1.5<BR>\n" );
document.write( "S = 26<BR>\n" );
document.write( "If he rode 26 miles on Saturday, then he rode 49-26, or 23 on Sunday.<br>Prove it: On Sunday he rode 10 miles more than one-half of his distance on Saturday.<BR>\n" );
document.write( "One-half of Saturday's distance is 26/2, or 13.<BR>\n" );
document.write( "Ten more than 13 is 23. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );