document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905679>Question 905679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 6 yards longer than its width the perimeter is 32 what is its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549360 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2 length + 2 width<BR>\n" );
document.write( "P = 32<BR>\n" );
document.write( "L = W+6<BR>\n" );
document.write( "Take the known value of L and put it into the initial equation<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "32 = 2(W+6) + 2W<BR>\n" );
document.write( "32 = 2W + 12 + 2W<BR>\n" );
document.write( "32 = 4W + 12<BR>\n" );
document.write( "Subtract 12 from each side<BR>\n" );
document.write( "20 = 4W<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "5 = W<BR>\n" );
document.write( "If the width is 5, then the length is 5+6, or 11<BR>\n" );
document.write( "5+5+11+11=32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );