document.write( "Question 905658: The length of the rectangle is 11 less than twice its width. If the perimeter is 86 what is the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #549301 by rm29924(97)\"\" \"About 
You can put this solution on YOUR website!
Let X = the width
\n" ); document.write( "the length is 11 less than twice the width so
\n" ); document.write( "Length = 2x-11\r
\n" ); document.write( "\n" ); document.write( "the perimeter of a rectangle = 2W + 2L so\r
\n" ); document.write( "\n" ); document.write( "2X + 2(2X-11) = 86
\n" ); document.write( "2X + 4X -22 = 86
\n" ); document.write( "add 22 to both sides
\n" ); document.write( "2X + 4X = 108
\n" ); document.write( "6X = 108
\n" ); document.write( "divide both sides by 6
\n" ); document.write( "X = 18\r
\n" ); document.write( "\n" ); document.write( "check the answer
\n" ); document.write( "2(18) + 2(2(18)-11) = 86
\n" ); document.write( "36 + 2(36-11) = 86
\n" ); document.write( "36 + 2(25) = 86
\n" ); document.write( "36 + 50 = 86
\n" ); document.write( "86 = 86 \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );