document.write( "Question 76599: Please find X and Y: 2X + 3Y = 16, 5X - 3Y = 44. \n" ); document.write( "
Algebra.Com's Answer #54929 by checkley75(3666)\"\" \"About 
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2x+3y=16
\n" ); document.write( "5x-3y=44 now add these two equations.
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\n" ); document.write( "7x=60
\n" ); document.write( "x=60/7 answer. now substitute (60/7) for x and solve for y
\n" ); document.write( "2*60/7+3y=16
\n" ); document.write( "120/7+3y=16
\n" ); document.write( "3y=16-120/7
\n" ); document.write( "3y=(7*16-120)/7
\n" ); document.write( "3y=(112-120)/7
\n" ); document.write( "3y=-8/7
\n" ); document.write( "y=-8/7*1/3
\n" ); document.write( "y=-8/21 answer.
\n" ); document.write( "proof.
\n" ); document.write( "5*60/7-3*-8/21=44
\n" ); document.write( "300/7+24/21=44
\n" ); document.write( "(300*3+24)/21=44
\n" ); document.write( "(900+24)/21=44
\n" ); document.write( "924/21=44
\n" ); document.write( "44=44\r
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