document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76596>Question 76596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are decreased by 3 cm, the area is decreased by 81 cm^2.  What were the dimensions of the original square?\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54924 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-3)(x-3)=x^2-81<BR>\n" );
document.write( "x^2-6x+9=x^2-81 the x^2 factors cancel out thus:<BR>\n" );
document.write( "-6x=-81-9<BR>\n" );
document.write( "-6x=-90<BR>\n" );
document.write( "x=-90/-6<BR>\n" );
document.write( "x=15 cm. the original length of the sides of the square.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "(15-3)(15-3)=12^2-81 <BR>\n" );
document.write( "12*12=15^2-81<BR>\n" );
document.write( "144=225-81<BR>\n" );
document.write( "144=144\r<BR>\n" );
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document.write( " </SPAN>\n" );
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