document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905467>Question 905467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of a 15% solution must be mixed with 20 liters of a 45 % solution to obtain a 25% solution?? My instructor shows us a box of 9 squares to solve this problem.  It does not make sense to me, is there another easier way??\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549226 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I enjoy doing those type problems but please post one at  a time.<BR>\n" );
document.write( "0.15*x+0.45*20=0.25(20+x)<BR>\n" );
document.write( "0.15*x+9=5+0.25x<BR>\n" );
document.write( "0.15x-0.25x=5-9<BR>\n" );
document.write( "-0.1x=-4<BR>\n" );
document.write( "x=40 gal of 15% is added to 20 gal of 45%  to get  60 gal  at 25%<BR>\n" );
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document.write( "0.15*40+0.45*20=0.25(20+40)<BR>\n" );
document.write( "6+9=0.25(60)<BR>\n" );
document.write( "15=15<BR>\n" );
document.write( "ok<BR>\n" );
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