document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905445>Question 905445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio between the perimeter and the width of a rectangle is 14 : 3. If the area of the rectangle is 108 sq. cm, what is the length of the rectangle?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549215 by </B><A HREF=/tutors/aboutme.mpl?userid=JoelSchwartz><B>JoelSchwartz(130)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JoelSchwartz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=108<BR>\n" );
document.write( "108=Lw<BR>\n" );
document.write( "w=108/L<BR>\n" );
document.write( "p/w=14/3<BR>\n" );
document.write( "p=2L+2w<BR>\n" );
document.write( "(2L+2w)/w=14/3<BR>\n" );
document.write( "2L+2w=14/3w<BR>\n" );
document.write( "2L+2(108/L)=14/3(108/L)<BR>\n" );
document.write( "2L+216/L=504/L<BR>\n" );
document.write( "2L^2=504-216<BR>\n" );
document.write( "2L^2=288<BR>\n" );
document.write( "L^2=144<BR>\n" );
document.write( "L=12<BR>\n" );
document.write( "w=108/12<BR>\n" );
document.write( "w=9<BR>\n" );
document.write( "p=2*12+2*9<BR>\n" );
document.write( "p=24+18<BR>\n" );
document.write( "p=42<BR>\n" );
document.write( "p/w=14/3<BR>\n" );
document.write( "42/9=14/3<BR>\n" );
document.write( "(42/9)/3=14/3<BR>\n" );
document.write( "(42/3)/(9/3)=14/3<BR>\n" );
document.write( "14/3=14/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );