document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905421>Question 905421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 16. one number is 4 less than 3 times the other. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549183 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 16\r<BR>\n" );
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document.write( "x = 3y - 4\r<BR>\n" );
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document.write( "3y - 4 + y = 16\r<BR>\n" );
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document.write( "4y - 4 = 16\r<BR>\n" );
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document.write( "4y = 16 + 4\r<BR>\n" );
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document.write( "4y = 20\r<BR>\n" );
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document.write( "y = 20/4\r<BR>\n" );
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document.write( "y = 5.\r<BR>\n" );
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document.write( "We now know that y = 5.\r<BR>\n" );
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document.write( "Let us plug y = 5 into either original equation to find x.\r<BR>\n" );
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document.write( "I will use x + y = 16.\r<BR>\n" );
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document.write( "x + 5 = 16\r<BR>\n" );
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document.write( "x = 16 - 5\r<BR>\n" );
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document.write( "x = 11\r<BR>\n" );
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document.write( "The two numbers are 5 and 11. </SPAN>\n" );
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