document.write( "Question 76558: Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y^3 - 13y^2 +54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height? \n" ); document.write( "
Algebra.Com's Answer #54918 by ankor@dixie-net.com(22740)\"\" \"About 
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Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y^3 - 13y^2 +54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
\n" ); document.write( ":
\n" ); document.write( "Find the product of the new length and height by dividing y^2 - 13y^2 + 54y - 72
\n" ); document.write( "by (y-6)
\n" ); document.write( "use synthetic division:
\n" ); document.write( ":....___________________________
\n" ); document.write( "+6 | 1 - 13 + 54 - 72
\n" ); document.write( "............+ 6 - 42 + 72
\n" ); document.write( "......------------------
\n" ); document.write( "........1 - 7 + 12 + 0
\n" ); document.write( ":
\n" ); document.write( "That gives us: y^2 - 7y + 12
\n" ); document.write( "This factors to: (y-3)(y-4)
\n" ); document.write( ":
\n" ); document.write( "The new length = (y-3)
\n" ); document.write( "The new height = (y-4)
\n" ); document.write( "or vice-vera \n" ); document.write( "
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