document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=905391>Question 905391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(6x-3)base 3=1+log(x-3)base3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #549166 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=549166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the bases of the logs are the same (number 3 in this case), then the insides must be equal. That is:\r<BR>\n" );
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document.write( "6x - 3 = 1 + x - 3\r<BR>\n" );
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document.write( "6x - x = 3 - 3 + 1\r<BR>\n" );
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document.write( "5x = 1\r<BR>\n" );
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document.write( "x = 1/5\r<BR>\n" );
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document.write( "Understand?\r<BR>\n" );
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document.write( " </SPAN>\n" );
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